Benzylamine $(C_6H_5CH_2NH_2)$ and aniline $(C_6H_5NH_2)$ can be distinguished by:

Assertion: Benzene diazonium chloride does not give a test for nitrogen.
Reason: Loss of $N_2$ gas takes place during heating.

Secondary nitro compounds when react with $HNO_2$ form crystalline solids which on treatment with $NaOH$ give

Carbylamine test is used in the detection of

Compound $P$ is neutral. $Q$ gives effervescence with $NaHCO_3$ while $R$ reacts with Hinsberg's reagent to give a solid soluble in $NaOH$. Compound $P$ is:

Match List-$I$ with List-$II$:

List-$I$ (Reagents used)	List-$II$ (Compound with functional group detected)
$A.$ Alkaline solution of copper sulphate and sodium citrate	$I.$ $C_6H_5CH(OH)CH_3$
$B.$ Neutral $FeCl_3$ solution	$II.$ $CH_3CH(NH_2)CH_3$
$C.$ Alkaline chloroform solution	$III.$ $C_6H_5CH_2CHO$
$D.$ Potassium iodide and sodium hypochlorite	$IV.$ $m-C_2H_5C_6H_4OH$

Choose the correct answer from the options given below: