Both husband and wife have normal vision,thou | vedclass

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(A) The correct answer is $A$ $(0\%)$.Given:$1$. Both husband and wife have normal vision.$2$. Both fathers were colour blind $(X^CY)$.$3$. Both mothe

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(A) The correct answer is $A$ $(0\%)$.Given:$1$. Both husband and wife have normal vision.$2$. Both fathers were colour blind $(X^CY)$.$3$. Both mothers were normal and did not carry the gene for colour blindness $(XX)$.Analysis:- The wife's father was colour blind $(X^CY)$,so she must have inherited the $X^C$ chromosome from him. Since she has normal vision,she must be a carrier $(X^CX)$.- The husband's father was colour blind $(X^CY)$,but the husband inherited his $X$ chromosome from his mother (who was $XX$). Therefore,the husband is normal $(XY)$.Cross:Parents: $XY$ (Husband) $	imes$ $X^CX$ (Wife)Gametes: $X, Y$ and $X^C, X$Offspring:- $X^CX$ (Carrier Daughter)- $XX$ (Normal Daughter)- $X^CY$ (Colour blind Son)- $XY$ (Normal Son)Conclusion:From the cross,the daughters are either carrier $(X^CX)$ or normal $(XX)$. None of the daughters are colour blind. Therefore,the probability of their daughters becoming colour blind is $0\%$.

Both husband and wife have normal vision,though their fathers were colour blind and their mothers did not have any gene for colour blindness. The probability of their daughters becoming colour blind is (in $\%$)

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