(A) $C_6H_5CH_2I$ is an alkyl halide where the iodine is attached to an $sp^3$ hybridized carbon,making it reactive towards nucleophilic substitution

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(A) $C_6H_5CH_2I$ is an alkyl halide where the iodine is attached to an $sp^3$ hybridized carbon,making it reactive towards nucleophilic substitution with $NaOH$ to produce $I^-$ ions. $C_6H_5I$ is an aryl halide where the iodine is attached to an $sp^2$ hybridized carbon,making it inert towards nucleophilic substitution under these conditions. When $AgNO_3$ is added to the acidified solution,$I^-$ ions react to form a yellow precipitate of $AgI$. Since $B$ gave a yellow precipitate,$B$ must be $C_6H_5CH_2I$. Therefore,$A$ must be $C_6H_5I$.

Class 12 Chemistry Haloalkanes and Haloarenes Properties of Haloalkanes

Bottles containing $C_6H_5I$ and $C_6H_5CH_2I$ lost their original labels. They were labelled $A$ and $B$ for testing. $A$ and $B$ were separately taken in test tubes and boiled with $NaOH$ solution. The end solution in each tube was made acidic with dilute $HNO_3$ and then some $AgNO_3$ solution was added. Substance $B$ gave a yellow precipitate. Which one of the following statements is true for this experiment?

AIEEE 2003 All AIEEE

A
$A$ was $C_6H_5I$
B
$A$ was $C_6H_5CH_2I$
C
$B$ was $C_6H_5I$
D
Addition of $HNO_3$ was unnecessary

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Chemistry Questions

Chapter

Haloalkanes and Haloarenes

Subtopic

Properties of Haloalkanes

Previous Year

AIEEE 2003 Paper All AIEEE years →

The following bimolecular elimination reaction $(E_2)$ is carried out with different halogen leaving groups. The per cent yield of the two products ($2$-hexene and $1$-hexene) for each leaving group is listed below.
Leaving group Conj. Acid $pK_a$ $\%$-yield of $2$-hexene $\%$-yield of $1$-hexene
$X = I$ $-10$ $81\%$ $19\%$
$X = Br$ $-9$ $72\%$ $28\%$
$X = Cl$ $-7$ $67\%$ $33\%$
$X = F$ $3.2$ $30\%$ $70\%$

Which of the following statement$(s)$ is/are true concerning this series of $E_2$ reactions?

Leaving group	Conj. Acid $pK_a$	$\%$-yield of $2$-hexene	$\%$-yield of $1$-hexene
$X = I$	$-10$	$81\%$	$19\%$
$X = Br$	$-9$	$72\%$	$28\%$
$X = Cl$	$-7$	$67\%$	$33\%$
$X = F$	$3.2$	$30\%$	$70\%$

Medium

View Solution

The correct sequence of reagents for the conversion of $X$ to $Y$ is :

DifficultJEE MAIN 2026

View Solution

$S_N^1$ and $S_N^2$ reactions are

Medium

View Solution

Chlorination of toluene in the presence of light and heat followed by reaction with aqueous $NaOH$ gives ...................

Medium

View Solution

The treatment of alkyl chlorides with aqueous $KOH$ leads to the formation of alcohols,but in the presence of alcoholic $KOH$,alkenes are the major products. Explain.

Easy

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

Similar Questions

The correct sequence of reagents for the conversion of $X$ to $Y$ is :

$S_N^1$ and $S_N^2$ reactions are

Chlorination of toluene in the presence of light and heat followed by reaction with aqueous $NaOH$ gives ...................

The treatment of alkyl chlorides with aqueous $KOH$ leads to the formation of alcohols,but in the presence of alcoholic $KOH$,alkenes are the major products. Explain.

Vedclass Test Series

Exam Paper Generator

Online Exam Module