By dissolving $0.35 \, \text{mole}$ of sodium chloride in water,$1.30 \, \text{L}$ of salt solution is obtained. The molarity of the resulting solution should be reported as $..... \, \text{M}$.

  • A
    $0.3$
  • B
    $0.269$
  • C
    $0.27$
  • D
    $0.2692$

Explore More

Similar Questions

$A$ solution contains $25\%$ ${H_2}O$,$25\%$ ${C_2}{H_5}OH$ and $50\%$ ${CH_3}COOH$ by mass. The mole fraction of ${H_2}O$ would be

Difficult
View Solution

Find out the molarity of a solution when $0.01 \ mol$ of a substance is dissolved in $10 \ g$ of water. (in $M$)

The density of a stock solution of $29.2\% \, (w/w) \, HCl$ is $1.25 \, g \, mL^{-1}$. If the molar mass of $HCl$ is $36.5 \, g \, mol^{-1}$,what volume (in $mL$) of the stock solution is required to prepare $200 \, mL$ of $0.4 \, M \, HCl$ solution?

If the density of a $2 \ M$ solution of ethylene glycol in water is $1.11 \ g/mL$, the molality (in $m$) of the solution is approximately

Two solutions of a substance are mixed as follows: $480 \ mL$ of $1.5 \ M$ first solution + $520 \ mL$ of $1.2 \ M$ second solution. The molarity of the final solution will be ............. $M$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo