By error,a student places a moving-coil voltmeter $V$ (nearly ideal) in series with the resistance in a circuit in order to read the current,as shown. The voltmeter reading will be ............ $V$.

To determine the resistance $(R)$ of a wire,a circuit is designed as shown below. The $V-I$ characteristic curve for this circuit is plotted for the voltmeter and the ammeter readings as shown in the figure. The value of $R$ is . . . . . . . $\Omega$.

The charge flowing through a resistance $R$ varies with time $t$ as $Q = at - bt^2$,where $a$ and $b$ are positive constants. The total heat produced in $R$ is

Find the current passing through the battery immediately after the key $(K)$ is closed. It is given that initially all the capacitors are uncharged. (Given that $E = 5 \, V$, $R = 6 \, \Omega$) (in $A$)

In the circuit element given here,if the potential at point $B$ is zero $(V_B = 0)$,then the potentials of points $A$ and $D$ are:

$A$ current of $2.0 \, A$ passes through a cell of $e.m.f.$ $1.5 \, V$ having an internal resistance of $0.15 \, \Omega$. The potential difference measured,in $volts$,across the terminals of the cell will be: