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(B) The molar mass of $CaCl_{2} = 40 + (2 	imes 35.5) = 111 \, g/mol$.Given mass of $CaCl_{2} = 222 \, g$.Number of moles of $CaCl_{2} = \frac{	ext{

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$3.6132 	imes 10^{24}$

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(B) The molar mass of $CaCl_{2} = 40 + (2 	imes 35.5) = 111 \, g/mol$.Given mass of $CaCl_{2} = 222 \, g$.Number of moles of $CaCl_{2} = \frac{	ext{Given mass}}{	ext{Molar mass}} = \frac{222}{111} = 2 \, mol$.According to the dissociation equation $CaCl_{2} ightarrow Ca^{2+} + 2Cl^{-}$,one formula unit of $CaCl_{2}$ produces $3$ ions ($1$ calcium ion and $2$ chloride ions).Therefore,$1 \, mol$ of $CaCl_{2}$ produces $3 \, mol$ of ions.$2 \, mol$ of $CaCl_{2}$ will produce $2 	imes 3 = 6 \, mol$ of ions.Total number of ions = $	ext{Number of moles} 	imes 	ext{Avogadro number} (N_{A})$.Total number of ions = $6 	imes 6.022 	imes 10^{23} = 36.132 	imes 10^{23} = 3.6132 	imes 10^{24}$ ions.

Calcium chloride when dissolved in water dissociates into its ions according to the following equation:
$CaCl_{2}(aq) \rightarrow Ca^{2+}(aq) + 2Cl^{-}(aq)$
Calculate the number of ions obtained from $CaCl_{2}$ when $222 \, g$ of it is dissolved in water.

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Calcium chloride when dissolved in water dissociates into its ions according to the following equation:$CaCl_{2}(aq) \rightarrow Ca^{2+}(aq) + 2Cl^{-}(aq)$Calculate the number of ions obtained from $CaCl_{2}$ when $222 \, g$ of it is dissolved in water.