(D) For $Cl$ $(Z=17, A=35)$: Protons $(p)$ = $Z = 17$. Electrons $(e^{-})$ = $Z = 17$. Neutrons $(n)$ = $A - Z = 35 - 17 = 18$. For $Cl^{-}$: Protons

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$Cl$: $e^{-}=17, p=17, n=18$; $Cl^{-}$: $e^{-}=18, p=17, n=18$; $Cl_{2}$: $e^{-}=34, p=34, n=36$

(D) For $Cl$ $(Z=17, A=35)$: Protons $(p)$ = $Z = 17$. Electrons $(e^{-})$ = $Z = 17$. Neutrons $(n)$ = $A - Z = 35 - 17 = 18$. For $Cl^{-}$: Protons $(p)$ = $17$. Electrons $(e^{-})$ = $17 + 1 = 18$. Neutrons $(n)$ = $18$. For $Cl_{2}$: Protons $(p)$ = $2 \times 17 = 34$. Electrons $(e^{-})$ = $2 \times 17 = 34$. Neutrons $(n)$ = $2 \times 18 = 36$.

Class 11 Chemistry Structure of Atom Atomic number, Mass number, Atomic species

Easy

Calculate the number of electrons,protons,and neutrons in $Cl_{2}$,$Cl$,and $Cl^{-}$. (Given for $Cl$: $Z = 17$ and $A = 35$)

A
$Cl$: $e^{-}=17, p=17, n=18$; $Cl^{-}$: $e^{-}=18, p=17, n=18$; $Cl_{2}$: $e^{-}=34, p=34, n=36$
B
$Cl$: $e^{-}=17, p=17, n=18$; $Cl^{-}$: $e^{-}=17, p=17, n=18$; $Cl_{2}$: $e^{-}=34, p=34, n=36$
C
$Cl$: $e^{-}=18, p=17, n=18$; $Cl^{-}$: $e^{-}=17, p=17, n=18$; $Cl_{2}$: $e^{-}=34, p=34, n=36$
D
$Cl$: $e^{-}=17, p=17, n=18$; $Cl^{-}$: $e^{-}=18, p=17, n=18$; $Cl_{2}$: $e^{-}=34, p=34, n=36$