Calculate the osmotic pressure of a solution | vedclass

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(D) The formula for osmotic pressure is $\pi = CRT$,where $C$ is the molar concentration,$R$ is the gas constant $(0.0821 \ L \ atm \ K^{-1} \ mol^{-1

Vedclass · Accepted Answer

$1.52$

Vedclass · Answer

(D) The formula for osmotic pressure is $\pi = CRT$,where $C$ is the molar concentration,$R$ is the gas constant $(0.0821 \ L \ atm \ K^{-1} \ mol^{-1})$,and $T$ is the temperature in Kelvin.$1$. Calculate the number of moles of glucose: $n = \frac{	ext{mass}}{	ext{molar mass}} = \frac{1.75 \ g}{180 \ g/mol} \approx 0.00972 \ mol$.$2$. Convert volume to liters: $V = 150 \ mL = 0.150 \ L$.$3$. Calculate molarity: $C = \frac{n}{V} = \frac{0.00972 \ mol}{0.150 \ L} \approx 0.0648 \ M$.$4$. Convert temperature to Kelvin: $T = 17 + 273 = 290 \ K$.$5$. Calculate osmotic pressure: $\pi = 0.0648 \ mol/L 	imes 0.0821 \ L \ atm \ K^{-1} \ mol^{-1} 	imes 290 \ K \approx 1.54 \ atm$. (Note: Using precise values,the result is approximately $1.52 \ atm$).

Calculate the osmotic pressure of a solution prepared by dissolving $1.75 \ g$ of glucose $(C_6H_{12}O_6)$ in $150 \ mL$ of solution at $17 \ ^oC$. (in $atm$)

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