Calculate the PV type of work for the followi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The work done in a $PV$ system is given by the formula $W = -P_{ext} \Delta V = -P_{ext}(V_2 - V_1)$.Initial volume $V_1 = 150 \ mL + 150 \ mL = 3

Vedclass · Accepted Answer

$15.00$

Vedclass · Answer

(C) The work done in a $PV$ system is given by the formula $W = -P_{ext} \Delta V = -P_{ext}(V_2 - V_1)$.Initial volume $V_1 = 150 \ mL + 150 \ mL = 300 \ mL = 0.3 \ dm^3$.Final volume $V_2 = 150 \ mL = 0.15 \ dm^3$.External pressure $P_{ext} = 1 \ bar$.Substituting the values: $W = -1 \ bar 	imes (0.15 \ dm^3 - 0.3 \ dm^3) = -1 	imes (-0.15) \ dm^3 \ bar = 0.15 \ dm^3 \ bar$.Since $1 \ dm^3 \ bar = 100 \ J$,the work done is $0.15 	imes 100 \ J = 15.00 \ J$.

Calculate the $PV$ type of work for the following reaction at $1 \ bar$ pressure. $C_3H_{6(g)} (150 \ mL) + HCl_{(g)} (150 \ mL) \longrightarrow C_3H_7Cl_{(g)} (150 \ mL)$ (in $J$)

Similar Questions

For $1 \text{ mole}$ of an ideal gas expanding isothermally from $1 \text{ L}$ to $10 \text{ L}$ at $300 \text{ K}$,the value of $\Delta U$ is: $(R = 2 \text{ cal mol}^{-1} \text{ K}^{-1})$

How will you calculate the work done on an ideal gas during compression,when the change in pressure is carried out in infinite steps?

Among the following,the set of parameters that represents path functions is:
$(a) \ q + w$
$(b) \ q$
$(c) \ w$
$(d) \ H - TS$

The difference between $\Delta H$ and $\Delta U$ is usually significant for systems consisting of:

Explain the enthalpy of dilution.

Vedclass Test Series

Exam Paper Generator

Online Exam Module