Calculate the energy per mole of photons of e | vedclass

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Question

(A) The energy of one photon is given by $E = \frac{hc}{\lambda}$.Given: $h = 6.626 	imes 10^{-34} \ J \ s$,$c = 3 	imes 10^8 \ m/s$,$\lambda = 700

Vedclass · Accepted Answer

$1.71 	imes 10^5 \ J/mol$

Vedclass · Answer

(A) The energy of one photon is given by $E = \frac{hc}{\lambda}$.Given: $h = 6.626 	imes 10^{-34} \ J \ s$,$c = 3 	imes 10^8 \ m/s$,$\lambda = 700 \ nm = 700 	imes 10^{-9} \ m$.Energy of one photon $E = \frac{6.626 	imes 10^{-34} 	imes 3 	imes 10^8}{700 	imes 10^{-9}} \ J = 2.84 	imes 10^{-19} \ J$.To find the energy per mole,multiply by Avogadro's number $(N_A = 6.022 	imes 10^{23} \ mol^{-1})$:$E_{mole} = E 	imes N_A = 2.84 	imes 10^{-19} 	imes 6.022 	imes 10^{23} \ J/mol \approx 1.71 	imes 10^5 \ J/mol$.

Calculate the energy per mole of photons of electromagnetic radiation having a wavelength of $700 \ nm$. $\left[h = 6.626 \times 10^{-34} \ J \ s, c = 3 \times 10^8 \ m/s, N_A = 6.022 \times 10^{23} \ mol^{-1}\right]$

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