Calculate the enthalpy change for the following reaction, using the given bond energies $(\text{kJ/mol})$: $C-H = 414$, $H-O = 463$, $H-Cl = 431$, $C-Cl = 326$, and $C-O = 335$.
$CH_3OH(g) + HCl(g) \rightarrow CH_3Cl(g) + H_2O(g)$

  • A
    $-23 \text{ kJ mol}^{-1}$
  • B
    $-42 \text{ kJ mol}^{-1}$
  • C
    $-59 \text{ kJ mol}^{-1}$
  • D
    $-51 \text{ kJ mol}^{-1}$

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