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Question

(C) According to the universal law of gravitation,the force of attraction between the Earth and the Sun is given by:$F = \frac{G 	imes M_{	ext{Sun}}

Vedclass · Accepted Answer

$3.57 	imes 10^{22} \, N$

Vedclass · Answer

(C) According to the universal law of gravitation,the force of attraction between the Earth and the Sun is given by:$F = \frac{G 	imes M_{	ext{Sun}} 	imes M_{	ext{Earth}}}{R^2}$Where:$M_{	ext{Sun}} = 2 	imes 10^{30} \, kg$$M_{	ext{Earth}} = 6 	imes 10^{24} \, kg$$R = 1.5 	imes 10^{11} \, m$$G = 6.7 	imes 10^{-11} \, Nm^2 \, kg^{-2}$Substituting the values:$F = \frac{6.7 	imes 10^{-11} 	imes 2 	imes 10^{30} 	imes 6 	imes 10^{24}}{(1.5 	imes 10^{11})^2}$$F = \frac{80.4 	imes 10^{43}}{2.25 	imes 10^{22}}$$F = 35.73 	imes 10^{21} \, N = 3.57 	imes 10^{22} \, N$Thus,the gravitational force is $3.57 	imes 10^{22} \, N$.

Calculate the force of gravitation between the Earth and the Sun,given that the mass of the Earth $= 6 \times 10^{24} \, kg$ and of the Sun $= 2 \times 10^{30} \, kg$. The average distance between the two is $1.5 \times 10^{11} \, m$.

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