Calculate the mass of a photon with wavelength $3.6 \, \mathring{A}$.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
Given wavelength $\lambda = 3.6 \, \mathring{A} = 3.6 \times 10^{-10} \, \text{m}$.
Velocity of photon $v$ is equal to the speed of light $c = 3 \times 10^8 \, \text{m s}^{-1}$.
Using the de Broglie relation $m = \frac{h}{\lambda v}$,where $h = 6.626 \times 10^{-34} \, \text{J s}$:
$m = \frac{6.626 \times 10^{-34} \, \text{J s}}{(3.6 \times 10^{-10} \, \text{m})(3 \times 10^8 \, \text{m s}^{-1})}$
$m = \frac{6.626 \times 10^{-34}}{10.8 \times 10^{-2}} \, \text{kg}$
$m = 6.135 \times 10^{-33} \, \text{kg}$.

Explore More

Similar Questions

The kinetic energy of a proton wave is $500 \ eV$. Calculate its de Broglie wavelength. (Mass of proton $= 1.67 \times 10^{-27} \ kg$)

Two particles $A$ and $B$ are in motion. If the wavelength associated with particle $A$ is $5 \times 10^{-8} \ m$,calculate the wavelength (in $\mathring{A}$) associated with particle $B$ if its momentum is half of $A$.

If the velocity of a hydrogen molecule is $5 \times 10^4 \, cm \, sec^{-1}$,then its de-Broglie wavelength is ............. $\mathring{A}$.

Difficult
View Solution

If the radius of the first orbit of hydrogen atom is $a_0$, then de Broglie's wavelength of electron in $3^{rd}$ orbit is (in $\pi a_0$)

Calculate the de-Broglie wavelength of an electron travelling at $1\%$ of the speed of light.

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo