Calculate the mass of urea [NH_2CONH_2] requi | vedclass

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(C) $0.25 \ m$ (molal) solution means $0.25 \ 	ext{moles}$ of urea are dissolved in $1000 \ g$ $(1 \ kg)$ of solvent.The molar mass of urea $[NH_2CON

Vedclass · Accepted Answer

$36.94$

Vedclass · Answer

(C) $0.25 \ m$ (molal) solution means $0.25 \ 	ext{moles}$ of urea are dissolved in $1000 \ g$ $(1 \ kg)$ of solvent.The molar mass of urea $[NH_2CONH_2]$ is $14 + 2 + 12 + 16 + 14 + 2 = 60 \ g/mol$.Mass of urea in $1000 \ g$ of solvent $= 0.25 \ 	ext{mol} 	imes 60 \ g/mol = 15 \ g$.Total mass of the solution $= 	ext{Mass of solute} + 	ext{Mass of solvent} = 15 \ g + 1000 \ g = 1015 \ g = 1.015 \ kg$.For $1.015 \ kg$ of solution,we need $15 \ g$ of urea.Therefore,for $2.5 \ kg$ of solution,the mass of urea required $= (15 \ g / 1.015 \ kg) 	imes 2.5 \ kg \approx 36.94 \ g$.

Calculate the mass of urea $[NH_2CONH_2]$ required in making $2.5 \ kg$ of $0.25 \ m$ aqueous solution. (in $g$)

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