Calculate the maximum acceleration (in m s^{- | vedclass

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(D) To keep the body stationary relative to the car,the pseudo force acting on the body must be balanced by the static frictional force.Let $m$ be the

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$1.5$

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(D) To keep the body stationary relative to the car,the pseudo force acting on the body must be balanced by the static frictional force.Let $m$ be the mass of the body and $a_{\max}$ be the maximum acceleration of the car.The pseudo force acting on the body is $F_p = m a_{\max}$.The maximum static frictional force is $f_{L} = \mu N = \mu mg$,where $\mu = 0.15$ is the coefficient of static friction.For the body to remain stationary,the pseudo force must not exceed the maximum static friction:$m a_{\max} \leq \mu mg$$a_{\max} \leq \mu g$Substituting the given values:$a_{\max} = 0.15 	imes 10 = 1.5 \, m s^{-2}$.

Calculate the maximum acceleration (in $m s^{-2}$) of a moving car so that a body lying on the floor of the car remains stationary. The coefficient of static friction between the body and the floor is $0.15$ $(g = 10 m s^{-2})$.

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