Calculate the molar conductivity of $0.2 \text{ M}$ $KCl$ solution at $298 \text{ K}$ given that the conductivity $\kappa = 0.0248 \text{ }\Omega^{-1} \text{cm}^{-1}$.
- A$143 \text{ }\Omega^{-1} \text{cm}^2 \text{mol}^{-1}$
- B$98 \text{ }\Omega^{-1} \text{cm}^2 \text{mol}^{-1}$
- C$124 \text{ }\Omega^{-1} \text{cm}^2 \text{mol}^{-1}$
- D$87 \text{ }\Omega^{-1} \text{cm}^2 \text{mol}^{-1}$
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The variation of molar conductivity with concentration of an electrolyte $X$ in aqueous solution is shown in the given figure.
The electrolyte $X$ is :
The electrolyte $X$ is :
The specific conductance of a solution depends upon -
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View SolutionThe resistance of a $0.1 \ N$ solution of acetic acid is $250 \ \Omega$ and the cell constant is $1.15 \ cm^{-1}$. The equivalent conductance of $0.1 \ N$ acetic acid in $\Omega^{-1} \ cm^2 \ eq^{-1}$ is:
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