Calculate the molar mass of a non-electrolyte solute when $6 \text{ g}$ of it is dissolved in $1 \text{ dm}^3$ of water, having an osmotic pressure of $2.4 \text{ atm}$ at $300 \text{ K}$ $(R = 0.0821 \text{ atm dm}^3 \text{ K}^{-1} \text{ mol}^{-1})$.
- A$45.0 \text{ g mol}^{-1}$
- B$74.12 \text{ g mol}^{-1}$
- C$61.58 \text{ g mol}^{-1}$
- D$90.28 \text{ g mol}^{-1}$
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