Calculate the molar mass of a solute at 300 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The formula for osmotic pressure is $\pi = \frac{W_2 RT}{M_2 V}$.Rearranging for molar mass: $M_2 = \frac{W_2 RT}{\pi V}$.Given: $W_2 = 400 \ mg =

Vedclass · Accepted Answer

$164 \ g \ mol^{-1}$

Vedclass · Answer

(C) The formula for osmotic pressure is $\pi = \frac{W_2 RT}{M_2 V}$.Rearranging for molar mass: $M_2 = \frac{W_2 RT}{\pi V}$.Given: $W_2 = 400 \ mg = 0.4 \ g$,$T = 300 \ K$,$V = 300 \ mL = 0.3 \ L$,$\pi = 0.2 \ atm$,$R = 0.0821 \ L \ atm \ K^{-1} \ mol^{-1}$.Substituting the values: $M_2 = \frac{0.4 \ g 	imes 0.0821 \ L \ atm \ K^{-1} \ mol^{-1} 	imes 300 \ K}{0.2 \ atm 	imes 0.3 \ L}$.$M_2 = \frac{9.852}{0.06} = 164.2 \ g \ mol^{-1} \approx 164 \ g \ mol^{-1}$.

Calculate the molar mass of a solute at $300 \ K$ if $400 \ mg$ of it is dissolved in $300 \ mL$ of water to exert an osmotic pressure of $0.2 \ atm$. $(R = 0.0821 \ L \ atm \ K^{-1} \ mol^{-1})$

Similar Questions

What is edema?

Which of the following pairs of solutions can be isotonic at the same temperature?

Give an example of a material used for making a semipermeable membrane for carrying out reverse osmosis.

Which of the following statements regarding isotonic solutions is $NOT$ correct?

Which inorganic precipitate acts as a semipermeable membrane,or what is the chemical composition of a semipermeable membrane?

Vedclass Test Series

Exam Paper Generator

Online Exam Module