(D) The molar mass of anhydrous calcium chloride $(CaCl_2)$ is $40 + 2 \times 35.5 = 111 \ g/mol$. Number of moles of $CaCl_2 = \frac{\text{Given mass

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(D) The molar mass of anhydrous calcium chloride $(CaCl_2)$ is $40 + 2 \times 35.5 = 111 \ g/mol$. Number of moles of $CaCl_2 = \frac{\text{Given mass}}{\text{Molar mass}} = \frac{222 \ g}{111 \ g/mol} = 2 \ mol$. Each mole of $CaCl_2$ dissociates to give $2 \ mol$ of $Cl^{-}$ ions. Total moles of $Cl^{-}$ ions $= 2 \times 2 \ mol = 4 \ mol$. Number of $Cl^{-}$ ions $= \text{moles} \times N_A = 4 \ N_A$.

Class 11 Chemistry Some Basic Concepts of Chemistry Chemical stoichiometry

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Calculate the number of $Cl^{-}$ ions in $222 \ g$ anhydrous calcium chloride? (At. mass $Ca=40, Cl=35.5$)

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A
$N_{A}$
B
$2 \ N_{A}$
C
$3 \ N_{A}$
D
$4 \ N_{A}$

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Calculate the number of $Cl^{-}$ ions in $222 \ g$ anhydrous calcium chloride? (At. mass $Ca=40, Cl=35.5$)

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