Calculate the osmotic pressure of $0.03 \ mol$ of non-electrolyte solute dissolved in $0.1 \ dm^3$ of water at $300 \ K \ [R=0.0821 \ dm^3 \ atm \ mol^{-1} \ K^{-1}]$ (in $atm$)

  • A
    $7.4$
  • B
    $6.4$
  • C
    $8.0$
  • D
    $5.6$

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Osmotic pressure is $0.0821 \ atm$ at a temperature of $300 \ K$. Find the concentration in $mol/L$.

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