Calculate the osmotic pressure of a 0.1 M aq | vedclass

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(C) The formula for osmotic pressure $(\pi)$ is given by: $\pi = i 	imes C 	imes R 	imes T$ Where: $i = 1.125$ (van't Hoff factor) $C = 0.1 \ M$ (m

Vedclass · Accepted Answer

$2.77$

Vedclass · Answer

(C) The formula for osmotic pressure $(\pi)$ is given by: $\pi = i 	imes C 	imes R 	imes T$ Where: $i = 1.125$ (van't Hoff factor) $C = 0.1 \ M$ (molar concentration) $R = 0.0821 \ atm \ dm^3 \ K^{-1} \ mol^{-1}$ (gas constant) $T = 300 \ K$ (temperature) Substituting the values: $\pi = 1.125 	imes 0.1 	imes 0.0821 	imes 300$ $\pi = 1.125 	imes 0.1 	imes 24.63$ $\pi = 1.125 	imes 2.463$ $\pi = 2.770875 \ atm$ Rounding to two decimal places,we get $\pi \approx 2.77 \ atm$.

Calculate the osmotic pressure of a $0.1 \ M$ aqueous solution of an electrolyte at $300 \ K$ if the van't Hoff factor is $1.125$. $[R = 0.0821 \ atm \ dm^3 \ K^{-1} \ mol^{-1}]$ (in $atm$)

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