Calculate the overall complex dissociation equilibrium constant for the $Cu(NH_3)_4^{2+}$ ion,given that $\beta_4$ for this complex is $2.1 \times 10^{13}$.
- A$4.7 \times 10^{-14}$
- B$2.1 \times 10^{-13}$
- C$4.7 \times 10^{13}$
- D$2.1 \times 10^{14}$
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