Calculate the power of an engine required to | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The work done $W$ in lifting a mass $m$ to a height $h$ against the gravitational force is given by $W = mgh$.Power $P$ is defined as the rate of

Vedclass · Accepted Answer

$10^{5} 	ext{ W}$

Vedclass · Answer

(B) The work done $W$ in lifting a mass $m$ to a height $h$ against the gravitational force is given by $W = mgh$.Power $P$ is defined as the rate of doing work,$P = \frac{W}{t}$.Given values are: $m = 10^{5} 	ext{ kg}$,$g = 10 	ext{ m s}^{-2}$,$h = 360 	ext{ m}$,and $t = 1 	ext{ hour} = 3600 	ext{ s}$.Substituting these values into the formula:$P = \frac{10^{5} 	imes 10 	imes 360}{3600}$$P = \frac{10^{6} 	imes 360}{3600}$$P = 10^{5} 	ext{ W}$.Thus,the power required is $10^{5} 	ext{ W}$.

Calculate the power of an engine required to lift $10^{5} \text{ kg}$ of coal per hour from a mine $360 \text{ m}$ deep. [Take $g = 10 \text{ m s}^{-2}$]

Similar Questions

$A$ light and a heavy object have the same momentum. Find out the ratio of their kinetic energies. Which one has a larger kinetic energy?

Name the practical unit of power in engineering.

$A$ spring which has been kept compressed by tying its ends together is allowed to be dissolved in an acid. What happens to the potential energy of the spring?

Which would have a greater effect on the kinetic energy of an object: doubling the mass,or doubling the velocity?

The work done on an object does not depend upon the

Vedclass Test Series

Exam Paper Generator

Online Exam Module