Difficult
Calculate the solubility of a gas in a solvent at a pressure of $3 \text{ atm}$ and $25 \text{ }^\circ\text{C}$. (Given: Henry's law constant $K_H = 3.0 \times 10^{-2} \text{ mol dm}^{-3} \text{ atm}^{-1}$) (in $\text{ M}$)
- A$0.07$
- B$0.08$
- C$0.09$
- D$0.1$
Explore More
Similar Questions
$A$ gas $X$ is dissolved in water at $2 \ bar$ pressure. Its mole fraction in the solution is $0.02$. Find the mole fraction of water in the solution when the pressure of the gas is doubled at the same temperature.
How many grams of water are required to dissolve $4 \ g$ of sodium sulfate at $323 \ K$? The solubility of sodium sulfate at this temperature is $16\%$.
Medium
View SolutionIn which solution,the solubility of the solute decreases with an increase in temperature?
The solubility of a gas in a liquid is directly proportional to the partial pressure of the gas. This statement is known as ...
Easy
View SolutionIf $N_2$ gas is bubbled through water at $293 \ K$,how many moles of $N_2$ gas would dissolve in $1 \ litre$ of water? Assume that $N_2$ exerts a partial pressure of $0.987 \ bar$. [Given $K_{H}$ for $N_2$ at $293 \ K$ is $76.48 \ kbar$]
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo