Calculate the solubility of gas in water at $1.2 \text{ atm}$ and $25^{\circ} C$ if Henry's law constant is $0.45 \text{ mol dm}^{-3} \text{ atm}^{-1}$ at $25^{\circ} C$.

  • A
    $0.45 \text{ mol dm}^{-3}$
  • B
    $0.54 \text{ mol dm}^{-3}$
  • C
    $0.25 \text{ mol dm}^{-3}$
  • D
    $0.31 \text{ mol dm}^{-3}$

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