Calculate the solubility product of sparingly soluble salt $BA$ at $300 \ K$ if its solubility is $9.1 \times 10^{-3} \ mol \ dm^{-3}$ at same temperature.
- A$9.635 \times 10^{-5}$
- B$9.012 \times 10^{-5}$
- C$8.281 \times 10^{-5}$
- D$7.816 \times 10^{-5}$
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