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Question

(A) For a simple cubic unit cell,the number of atoms per unit cell $(n)$ is $1$.Total volume occupied by atoms in the unit cell $= n 	imes \frac{4}{3

Vedclass · Accepted Answer

$1.13 	imes 10^{-22} \ cm^3$

Vedclass · Answer

(A) For a simple cubic unit cell,the number of atoms per unit cell $(n)$ is $1$.Total volume occupied by atoms in the unit cell $= n 	imes \frac{4}{3} \pi r^3$.Given $r = 3 	imes 10^{-8} \ cm$.Volume $= 1 	imes \frac{4}{3} 	imes 3.14159 	imes (3 	imes 10^{-8} \ cm)^3$.Volume $= \frac{4}{3} 	imes 3.14159 	imes 27 	imes 10^{-24} \ cm^3$.Volume $= 4 	imes 3.14159 	imes 9 	imes 10^{-24} \ cm^3$.Volume $= 113.097 	imes 10^{-24} \ cm^3 = 1.13 	imes 10^{-22} \ cm^3$.

Calculate the total volume occupied by all atoms in a simple cubic unit cell if the radius of the atom is $3 \times 10^{-8} \ cm$.

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