Calculate the velocity of an electron having | vedclass

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Question

(C) According to the de Broglie equation,$\lambda = \frac{h}{mv}$.Rearranging for velocity,we get $v = \frac{h}{m \lambda}$.Given values: $h = 6.63

Vedclass · Accepted Answer

$1.26 	imes 10^4 \ ms^{-1}$

Vedclass · Answer

(C) According to the de Broglie equation,$\lambda = \frac{h}{mv}$.Rearranging for velocity,we get $v = \frac{h}{m \lambda}$.Given values: $h = 6.63 	imes 10^{-34} \ Js$,$m = 9.1 	imes 10^{-31} \ kg$,and $\lambda = 58 \ nm = 58 	imes 10^{-9} \ m$.Substituting these values into the formula:$v = \frac{6.63 	imes 10^{-34}}{(9.1 	imes 10^{-31}) 	imes (58 	imes 10^{-9})}$$v = \frac{6.63 	imes 10^{-34}}{527.8 	imes 10^{-40}}$$v = \frac{6.63}{527.8} 	imes 10^6 \ ms^{-1}$$v \approx 0.01256 	imes 10^6 \ ms^{-1} = 1.256 	imes 10^4 \ ms^{-1}$.Rounding to the nearest option,the velocity is $1.26 	imes 10^4 \ ms^{-1}$.

Calculate the velocity of an electron having a de Broglie wavelength of $58 \ nm$ and mass $9.1 \times 10^{-31} \ kg$. Given: $h = 6.63 \times 10^{-34} \ Js$.

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