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Question

(C) The work done in a chemical reaction at constant pressure is given by the formula: $W = -\Delta n_g RT$. First,calculate the change in the number

Vedclass · Accepted Answer

$2494$

Vedclass · Answer

(C) The work done in a chemical reaction at constant pressure is given by the formula: $W = -\Delta n_g RT$. First,calculate the change in the number of moles of gaseous species,$\Delta n_g$: $\Delta n_g = (n_{products}) - (n_{reactants}) = (2 + 2) - (4 + 1) = 4 - 5 = -1$. Now,substitute the values into the work formula: $W = -(-1) 	imes 8.314 \ J \ K^{-1} \ mol^{-1} 	imes 300 \ K$. $W = 1 	imes 8.314 	imes 300 \ J = 2494.2 \ J$. Rounding to the nearest integer,the work done is $2494 \ J$.

Calculate the work done in the following reaction at $300 \ K$ and at constant pressure. $(R = 8.314 \ J \ K^{-1} \ mol^{-1})$ $4 \ HCl_{(g)} + O_{2_{(g)}} \rightarrow 2 \ Cl_{2_{(g)}} + 2 \ H_2O_{(g)}$ (in $J$)

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