Capacitive reactance of a capacitor in an AC | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The capacitive reactance $X_C$ of a capacitor is given by the formula $X_C = \frac{1}{2 \pi f C}$,where $f$ is the frequency of the $AC$ source an

Vedclass · Accepted Answer

$3 \ k\Omega$

Vedclass · Answer

(B) The capacitive reactance $X_C$ of a capacitor is given by the formula $X_C = \frac{1}{2 \pi f C}$,where $f$ is the frequency of the $AC$ source and $C$ is the capacitance.From this relation,we can see that $X_C \propto \frac{1}{f}$.Let the initial frequency be $f_1$ and the initial reactance be $X_{C1} = 6 \ k\Omega$.Let the new frequency be $f_2 = 2f_1$.The new reactance $X_{C2}$ is given by the ratio:$\frac{X_{C2}}{X_{C1}} = \frac{f_1}{f_2} = \frac{f_1}{2f_1} = \frac{1}{2}$.Therefore,$X_{C2} = \frac{X_{C1}}{2} = \frac{6 \ k\Omega}{2} = 3 \ k\Omega$.

Capacitive reactance of a capacitor in an $AC$ circuit is $6 \ k\Omega$. If the same capacitor is connected to an $AC$ source of double the frequency,the capacitive reactance will become

Similar Questions

In the case of an inductor,

An alternating e.m.f. is applied to a purely capacitive circuit. What is the phase relation between the e.m.f. and the current flowing in the circuit?

An inductance of $1 \ H$ is connected in series with an $AC$ source of $220 \ V$ and $50 \ Hz$. The inductive reactance (in ohm) is: (in $\pi$)

An inductor,a resistor,and a capacitor are joined in series with an $AC$ source. As the frequency of the source is slightly increased from a very low value,the reactance of the

What is the phase difference between voltage $V$ and current $I$ in an $AC$ circuit containing only a capacitor?

Vedclass Test Series

Exam Paper Generator

Online Exam Module