A carbon resistor has a resistance specified | vedclass

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Question

(A) The initial resistance $R_i$ is determined by the color code: Red $(2)$,Yellow $(4)$,Black $(10^0)$. Thus,$R_i = 24 	imes 10^0 = 24 \, \Omega$.Wh

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White,Blue,Black

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(A) The initial resistance $R_i$ is determined by the color code: Red $(2)$,Yellow $(4)$,Black $(10^0)$. Thus,$R_i = 24 	imes 10^0 = 24 \, \Omega$.When a wire is stretched to twice its length $(L_f = 2L_i)$,its cross-sectional area $A$ decreases such that $A_f = A_i / 2$ (since volume $V = AL$ is constant).The new resistance $R_f$ is given by $R_f = ho (L_f / A_f) = ho (2L_i / (A_i / 2)) = 4 ho (L_i / A_i) = 4 R_i$.Therefore,$R_f = 4 	imes 24 = 96 \, \Omega$.The new resistance $96 \, \Omega$ can be written as $9.6 	imes 10^1 \, \Omega$. However,standard color codes use integer values. Checking the options,$96 \, \Omega$ is closest to $96 	imes 10^0 \, \Omega$. The color code for $9$ is White,$6$ is Blue,and $10^0$ is Black. Thus,the new color code is White,Blue,Black.

$A$ carbon resistor has a resistance specified by three bands with colors red,yellow,and black. If the resistor is remolded to make a resistor twice its previous length,what will be the new color code?

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