A certain force acting on a 20 , kg mass chan | vedclass

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Question

(D) Given:Mass $(m)$ $= 20 \, kg$Initial velocity $(u)$ $= 5 \, m \, s^{-1}$Final velocity $(v)$ $= 2 \, m \, s^{-1}$According to the Work-Energy Theo

Vedclass · Accepted Answer

$210$

Vedclass · Answer

(D) Given:Mass $(m)$ $= 20 \, kg$Initial velocity $(u)$ $= 5 \, m \, s^{-1}$Final velocity $(v)$ $= 2 \, m \, s^{-1}$According to the Work-Energy Theorem, the work done by a force is equal to the change in kinetic energy of the object.Work done $(W)$ $= \Delta KE = KE_{final} - KE_{initial}$$W = \frac{1}{2} m v^2 - \frac{1}{2} m u^2$$W = \frac{1}{2} m (v^2 - u^2)$Substituting the values:$W = \frac{1}{2} 	imes 20 	imes (2^2 - 5^2)$$W = 10 	imes (4 - 25)$$W = 10 	imes (-21)$$W = -210 \, J$Since the question asks for the magnitude of work done by the force (which is a retarding force), the absolute value is $210 \, J$.

$A$ certain force acting on a $20 \, kg$ mass changes its velocity from $5 \, m \, s^{-1}$ to $2 \, m \, s^{-1}$. Calculate the work done by the force. (in $J$)

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