Change in volume when 10 , mL of phosphine (P | vedclass

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(C) The given balanced chemical equation is: $2PH_{3(g)} \rightarrow 2P_{(s)} + 3H_{2(g)}$.According to Avogadro's law,at constant temperature and pre

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$5 \, mL$ increase

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(C) The given balanced chemical equation is: $2PH_{3(g)} ightarrow 2P_{(s)} + 3H_{2(g)}$.According to Avogadro's law,at constant temperature and pressure,the volume of gases is proportional to the number of moles.In the reaction,$2 \, 	ext{moles}$ of gaseous $PH_3$ produce $3 \, 	ext{moles}$ of gaseous $H_2$ (since $P_{(s)}$ is a solid,its volume is negligible).Thus,$2 \, 	ext{volumes}$ of $PH_3$ produce $3 \, 	ext{volumes}$ of $H_2$.For $10 \, mL$ of $PH_3$,the volume of $H_2$ produced is: $(3 / 2) 	imes 10 \, mL = 15 \, mL$.The change in volume is: $15 \, mL - 10 \, mL = 5 \, mL$ increase.

Change in volume when $10 \, mL$ of phosphine $(PH_3)$ is decomposed according to the reaction: $2PH_{3(g)} \rightarrow 2P_{(s)} + 3H_{2(g)}$.

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