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(C) The chemical $A$ is calcium hydroxide,$Ca(OH)_2$,also known as slaked lime.$1$. $Ca(OH)_2$ is used in the Clark's process to remove temporary hard

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$Ca(OH)_2$

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(C) The chemical $A$ is calcium hydroxide,$Ca(OH)_2$,also known as slaked lime.$1$. $Ca(OH)_2$ is used in the Clark's process to remove temporary hardness of water by converting soluble bicarbonates into insoluble carbonates: $Ca(HCO_3)_2 + Ca(OH)_2 \rightarrow 2CaCO_3 \downarrow + 2H_2O$.$2$. It reacts with sodium carbonate $(Na_2CO_3)$ to produce caustic soda $(NaOH)$: $Ca(OH)_2 + Na_2CO_3 \rightarrow CaCO_3 + 2NaOH$.$3$. When $CO_2$ is passed through lime water $(Ca(OH)_2)$,it turns milky due to the formation of insoluble $CaCO_3$: $Ca(OH)_2 + CO_2 \rightarrow CaCO_3 \downarrow + H_2O$.

Chemical $A$ is used for water softening to remove temporary hardness. $A$ reacts with sodium carbonate to generate caustic soda. When $CO_2$ is bubbled through $A$,it turns cloudy,what is $A$?

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