A chemist added an extra 0.5 mole of EtLi in | vedclass

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Question

(C) The reaction of a carboxylic acid with organolithium reagents $(EtLi)$ proceeds through the formation of a dilithio species. First,$1 \ equivalent

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(C) The reaction of a carboxylic acid with organolithium reagents $(EtLi)$ proceeds through the formation of a dilithio species. First,$1 \ equivalent$ of $EtLi$ deprotonates the carboxylic acid to form a lithium carboxylate. Then,$2 \ equivalents$ of $EtLi$ attack the carbonyl carbon to form a stable tetrahedral intermediate (a gem-diol dianion derivative). Upon acidic workup $(H_3O^+)$,this intermediate collapses to form a ketone. Since the starting material is a hydroxy acid,the reaction specifically yields an $\alpha$-hydroxy ketone as shown in the provided mechanism.

$A$ chemist added an extra $0.5 \ mole$ of $EtLi$ in the above reaction to obtain product $(A)$. What is the product $(A)$?

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