Chloride ion (Cl^-) and potassium ion (K^+) a | vedclass

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Question

(D) Chloride ion $(Cl^-)$ and potassium ion $(K^+)$ are isoelectronic,meaning they have the same number of electrons ($18$ electrons each).For isoelec

Vedclass · Accepted Answer

Chloride ion is bigger than potassium ion

Vedclass · Answer

(D) Chloride ion $(Cl^-)$ and potassium ion $(K^+)$ are isoelectronic,meaning they have the same number of electrons ($18$ electrons each).For isoelectronic species,the ionic radius decreases as the nuclear charge (atomic number) increases.The atomic number of $Cl$ is $17$,while the atomic number of $K$ is $19$.Since $K^+$ has a higher nuclear charge $(Z = 19)$ than $Cl^-$ $(Z = 17)$,the electrons in $K^+$ are more strongly attracted by the nucleus.Therefore,the ionic radius of $Cl^-$ is larger than that of $K^+$.

Chloride ion $(Cl^-)$ and potassium ion $(K^+)$ are isoelectronic. Then:

Similar Questions

Assertion $(A)$: The ionic radii of $Na^{+}$ and $F^{-}$ are same.
Reason $(R)$: Both $Na^{+}$ and $F^{-}$ are isoelectronic species.
The correct answer is:

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Which of the following ions is the smallest in size?

Which of the following is the incorrect order of ionic/atomic radius?

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