Chlorination of toluene in the presence of li | vedclass

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(D) $1$. Chlorination of toluene in the presence of light and heat (free radical substitution) leads to the formation of benzal chloride $(C_6H_5CHCl_

Vedclass · Accepted Answer

Benzyl alcohol

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(D) $1$. Chlorination of toluene in the presence of light and heat (free radical substitution) leads to the formation of benzal chloride $(C_6H_5CHCl_2)$ or benzotrichloride $(C_6H_5CCl_3)$ depending on the amount of chlorine used. However,the standard reaction for this sequence typically refers to the formation of benzaldehyde upon hydrolysis. If the question implies side-chain chlorination followed by hydrolysis,it yields benzaldehyde. $2$. Re-evaluating the options: None of the options match benzaldehyde. $3$. If the question implies chlorination of the ring (electrophilic substitution) followed by $NaOH$ treatment,it would yield chlorotoluene,not cresol. $4$. Given the options provided,there is a discrepancy. However,if we assume the question meant the hydrolysis of benzyl chloride $(C_6H_5CH_2Cl)$,the product is benzyl alcohol $(C_6H_5CH_2OH)$. This is the most chemically consistent answer among the choices.

Chlorination of toluene in the presence of light and heat followed by treatment with aqueous $NaOH$ gives :

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