Chlorophyll in green plants absorbs light of frequency $4.620 \times 10^{14} \ Hz$. Find the wavelength and the region in the electromagnetic spectrum.
(N/A) The wavelength $\lambda$ is calculated using the formula $\lambda = \frac{c}{\nu}$,where $c = 3.0 \times 10^8 \ m \ s^{-1}$ and $\nu = 4.620 \times 10^{14} \ Hz$.
$\lambda = \frac{3.0 \times 10^8 \ m \ s^{-1}}{4.620 \times 10^{14} \ Hz} = 0.6494 \times 10^{-6} \ m$.
Converting to nanometers: $\lambda = 0.6494 \times 10^{-6} \ m \times 10^9 \ nm/m = 649.4 \ nm$.
The visible spectrum range is approximately $400 \ nm$ to $750 \ nm$. Since $649.4 \ nm$ falls within this range,it belongs to the visible region.
$\lambda = \frac{3.0 \times 10^8 \ m \ s^{-1}}{4.620 \times 10^{14} \ Hz} = 0.6494 \times 10^{-6} \ m$.
Converting to nanometers: $\lambda = 0.6494 \times 10^{-6} \ m \times 10^9 \ nm/m = 649.4 \ nm$.
The visible spectrum range is approximately $400 \ nm$ to $750 \ nm$. Since $649.4 \ nm$ falls within this range,it belongs to the visible region.
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