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(B) The work done by an external agent to move a charge $q$ from point $A$ to point $B$ is given by $W_{ext} = q(V_B - V_A)$.For option $B$: Moving a

Vedclass · Accepted Answer

Work done by an external agent to move a positive charge from a lower potential to a higher potential is positive.

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(B) The work done by an external agent to move a charge $q$ from point $A$ to point $B$ is given by $W_{ext} = q(V_B - V_A)$.For option $B$: Moving a positive charge $(q > 0)$ from lower potential $(V_A)$ to higher potential $(V_B)$ means $V_B > V_A$,so $V_B - V_A > 0$. Thus,$W_{ext} = q(V_B - V_A) > 0$. This is positive.For option $A$: Moving a negative charge $(q  0$. This is positive,not negative.For option $C$: Work done by the electric field $W_{field} = -\Delta U = -(U_{final} - U_{initial})$. If moving from higher potential energy to lower potential energy,$U_{final} Therefore,option $B$ is the correct statement.

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