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Question

(A) To solve this,we divide the series into groups of equal length. The total number of letters is $16$. We can divide it into $4$ groups of $4$ lette

Vedclass · Accepted Answer

$abba$

Vedclass · Answer

(A) To solve this,we divide the series into groups of equal length. The total number of letters is $16$. We can divide it into $4$ groups of $4$ letters each: $(abb.) ( . . ba) (a. . . ) (bab.) ( . . ab) (a)$. This does not seem to fit perfectly. Let's look at the pattern $abb. / . baa / . a. . / bab. / . aba$. By observing the sequence,we can identify a repeating pattern of $abba$.
If we fill the blanks with $abba$,the series becomes: $abba / abba / abba / abba / abba$.
Thus,the missing letters are $a, b, b, a$.

Choose the correct alternative to fill in the blanks in the series: $abb . . . . baa . . . . a . . . bab . . . . aba$

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