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Question

(C) To solve this,we count the total number of characters including blanks: $20$.
We can divide the series into groups of $4$ characters: $(abac), (a

Vedclass · Accepted Answer

$cabc$

Vedclass · Answer

(C) To solve this,we count the total number of characters including blanks: $20$.
We can divide the series into groups of $4$ characters: $(abac), (abac), (abac), (abac), (abac)$.
Let's break the given sequence: $aba(c) / baca / (a)ba(c) / baca / abac / (a)ca$.
Wait,let's re-examine the pattern: $abac / abac / abac / abac / abac$.
Given sequence: $aba . baca . . ba . . bacaabac . . aca$.
Actually,the pattern is $abac$ repeated.
Filling the blanks: $aba(c) / baca / (a)ba(c) / baca / abac / (a)ca$.
Wait,the sequence is $aba(c) / baca / (a)ba(c) / baca / abac / (a)ca$.
Let's try filling $c, a, b, c$: $aba(c) / baca / (a)ba(c) / baca / abac / (a)ca$.
Correct pattern is $abac$ repeated $5$ times.
$aba(c) / baca / (a)ba(c) / baca / abac / (a)ca$.
The missing letters are $c, a, b, c$. Thus,option $C$ is correct.

Choose the correct alternative to complete the series: $aba...baca....ba....bacaabac....aca$

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Choose the correct alternative to complete the series: $aba...baca....ba....bacaabac....aca$

Similar Questions

Fill in the blank space for the given series with the correct alternative.$3, 10, 20, 33, 49, 68, (\ldots)$

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