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Question

(C) To solve the series $abc....d....be....d....b...cda$,we count the total number of characters including blanks. There are $20$ positions.
We divid

Vedclass · Accepted Answer

$dacab$

Vedclass · Answer

(C) To solve the series $abc....d....be....d....b...cda$,we count the total number of characters including blanks. There are $20$ positions.
We divide the series into groups of $4$ characters: $(abc.) (d.be) (.d.b) (.cda)$.
By observing the pattern,we can see that each group follows the sequence $a, b, c, d, e$ in a cyclic or shifting manner.
Let's test the option $dacab$:
Filling the blanks: $a b c (d) / (a) d b e / (c) d (a) b / (b) c d a$.
This forms the pattern $abcd, adbe, cdab, bcda$,which is a logical rotation.
Thus,the correct sequence is $dacab$.

Choose the correct alternative to complete the series: $abc....d....be....d....b...cda$

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