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(D) To solve the series $gfe....ig....eii...fei....gf....ii$,let us count the total number of characters including blanks.There are $20$ positions in

Vedclass · Accepted Answer

$ifige$

Vedclass · Answer

(D) To solve the series $gfe....ig....eii...fei....gf....ii$,let us count the total number of characters including blanks.There are $20$ positions in total.We can divide the series into groups of $4$ characters: $(gfe_) (i_ig) (_eii) (fei_) (gf_i) (i)$.Looking at the pattern,the sequence repeats as $gfei$.Let's fill the blanks:$gfe(i) / (f)ig(e) / (g)eii / fei(g) / gf(e)i / i$.Wait,let's re-examine the pattern: $gfei, gfei, gfei, gfei, gfei$.Filling the blanks: $gfe(i) / (f)ig(e) / (g)eii / fei(g) / gf(e)i / i$.Actually,the pattern is $gfei$ repeated. $gfe(i) / (f)ig(e) / (g)eii / fei(g) / gf(e)i / i$ does not fit perfectly.Let's try grouping by $4$: $gfe_ / i_ig / _eii / fei_ / gf_i / i$.Correct pattern: $gfei, gfei, gfei, gfei, gfei$.$gfe(i) / (f)ig(e) / (g)eii / fei(g) / gf(e)i / i$.The missing letters are $i, f, e, g, e$.Thus,the correct option is $ifige$.

Choose the correct alternative to complete the series: $gfe....ig....eii...fei....gf....ii$

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