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Question

(A) To solve this,we look for a repeating pattern in the series: $....a...b...abaa...bab...abb$. By observing the sequence,we can divide it into group

Vedclass · Accepted Answer

$aaabb$

Vedclass · Answer

(A) To solve this,we look for a repeating pattern in the series: $....a...b...abaa...bab...abb$. By observing the sequence,we can divide it into groups of $3$: $baa / bba / baa / bba / baa / bb$. Filling the blanks with the missing letters: $1^{st}$ blank: $b$ $2^{nd}$ blank: $a$ $3^{rd}$ blank: $a$ $4^{th}$ blank: $b$ $5^{th}$ blank: $b$ Thus,the missing sequence is $baabb$.

Choose the correct alternative to complete the series: $....a...b...abaa...bab...abb$

Similar Questions

Choose the correct alternative for the missing terms in the series: $R, M, ?, F, D, ?$

Find out the wrong term from the given series: $3, 10, 27, 4, 16, 64, 5, 25, 125$.

Fill in the blank space for the given series with the correct alternative.
$9, 11, 20, 31, (...), 82$

How many such numbers are there in the following series,each of which is immediately preceded by $6$ but not immediately followed by $4$?
$3, 8, 6, 8, 4, 2, 6, 9, 8, 4, 6, 8, 4, 8, 6, 2, 6, 8, 4, 8$

Choose the correct alternative to complete the series: $ccbab...caa...bccc...a$

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