Choose the correct decreasing order of reactivity of alkyl halides towards $S_{N}1$ reaction.
- APrimary halide $>$ Secondary halide $>$ Tertiary halide
- BSecondary halide $>$ Tertiary halide $>$ Primary halide
- CTertiary halide $>$ Secondary halide $>$ Primary halide
- DTertiary halide $>$ Primary halide $>$ Secondary halide
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Similar Questions
Consider the $S_N1$ solvolysis of the following halides in aqueous formic acid:
$(I)$ $CH_3-CH(CH_3)-CH(Br)-CH_3$
$(II)$ $CH_3-C(CH_3)(Br)-CH_3$
$(III)$ $C_6H_5-CH(Br)-C_6H_5$
$(IV)$ $C_6H_5-CH(Br)-CH_3$
Which one of the following is the correct sequence of the halides given above in the decreasing order of their reactivity?
$(I)$ $CH_3-CH(CH_3)-CH(Br)-CH_3$
$(II)$ $CH_3-C(CH_3)(Br)-CH_3$
$(III)$ $C_6H_5-CH(Br)-C_6H_5$
$(IV)$ $C_6H_5-CH(Br)-CH_3$
Which one of the following is the correct sequence of the halides given above in the decreasing order of their reactivity?
Among $CH_3F$,$CH_3Cl$,$CH_3Br$,and $CH_3I$,which one does not give methane on reduction?
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View SolutionIn the following reaction $C_{6}H_{5}CH_{2}Br \xrightarrow[(ii)H_{3}O^{+}]{(i)Mg, \text{Ether}} X$
Product $X$ is
Product $X$ is
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View SolutionThe product formed on the reaction of ethyl alcohol with bleaching powder is:
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View SolutionHow many different products are formed from the $E_2$ elimination reaction of the following alkyl iodide?
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