Choose the correct matching:-

Co | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(NONE) $(P) NaBr + 	ext{conc. } H_2SO_4 ightarrow NaHSO_4 + HBr$. $HBr$ is oxidized to $Br_2$ (brown colour) and $SO_2$ (colourless gas,paramagneti

Vedclass · Accepted Answer

$P-B, D; Q-A, C; R-B; S-B, D$

Vedclass · Answer

(NONE) $(P) NaBr + 	ext{conc. } H_2SO_4 ightarrow NaHSO_4 + HBr$. $HBr$ is oxidized to $Br_2$ (brown colour) and $SO_2$ (colourless gas,paramagnetic). Thus,$P-B, D$.
$(Q) Na_2S + 	ext{dil. } HCl ightarrow 2NaCl + H_2S$. $H_2S$ is a colourless gas with a rotten egg smell. Thus,$Q-A, C$.
$(R) NaNO_2 + 	ext{dil. } HCl ightarrow NaCl + HNO_2$. $HNO_2$ decomposes to $NO$ (colourless gas,paramagnetic). Thus,$R-A, D$.
$(S) NaNO_3 + 	ext{conc. } H_2SO_4 ightarrow NaHSO_4 + HNO_3$. $HNO_3$ decomposes to $NO_2$ (brown colour,paramagnetic). Thus,$S-B, D$.
The correct matching is $P-B, D; Q-A, C; R-A, D; S-B, D$.

Column-$I$	Column-$II$
$(P) NaBr + \text{conc. } H_2SO_4 \rightarrow$	$(A) \text{Colourless gas}$
$(Q) Na_2S + \text{dil. } HCl \rightarrow$	$(B) \text{Brown colour}$
$(R) NaNO_2 + \text{dil. } HCl \rightarrow$	$(C) \text{Rotten smell}$
$(S) NaNO_3 + \text{conc. } H_2SO_4 \rightarrow$	$(D) \text{Paramagnetic}$

Similar Questions

Which anion of a sodium salt gives a white precipitate upon heating with a magnesium salt?

The salt which responds to dilute and concentrated $H_2SO_4$ is

In the brown ring test,the brown color for $NO_2^-$ and $NO_3^-$ is due to the formation of which complex ion?

Which of the following ions will not give a precipitate with $AgNO_3$?

When a few drops of $KMnO_4$ are added to an acidic solution of an anion,which of the following,if present,will $NOT$ decolorize $KMnO_4$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module