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(C) The given molecule is $1,4-dichlorobuta-1,2,3-triene$.In cumulenes with an even number of double bonds,the terminal groups lie in perpendicular pl

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both $(a)$ and $(b)$

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(C) The given molecule is $1,4-dichlorobuta-1,2,3-triene$.In cumulenes with an even number of double bonds,the terminal groups lie in perpendicular planes.Since the molecule has three double bonds (an odd number of $\pi$ bonds between the terminal carbons),the terminal $CH-Cl$ groups lie in perpendicular planes.This makes the molecule non-planar.Due to the perpendicular arrangement of the terminal groups,the dipole moments of the two $C-Cl$ bonds do not cancel each other out,resulting in a non-zero net dipole moment $(\mu 
eq 0)$.Therefore,the molecule is non-planar and has a non-zero dipole moment.

Choose the correct option for the following molecule in view of chemical bonding:
$Cl-CH=C=C=CH-Cl$

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Choose the correct option for the following molecule in view of chemical bonding:$Cl-CH=C=C=CH-Cl$