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(A) $1$. For $M.P.$ of alkaline earth metal fluorides: $BeF_2$ is covalent,while $MgF_2$ and $CaF_2$ are ionic. The lattice energy decreases as the si

Vedclass · Accepted Answer

$M.P.: CaF_2 > MgF_2 > BeF_2$;$S: MgF_2 < CaF_2 < BeF_2$

Vedclass · Answer

(A) $1$. For $M.P.$ of alkaline earth metal fluorides: $BeF_2$ is covalent,while $MgF_2$ and $CaF_2$ are ionic. The lattice energy decreases as the size of the cation increases,but $BeF_2$ has a significantly lower melting point due to its covalent nature. The correct order is $CaF_2 > MgF_2 > BeF_2$.$2$. For solubility $(S)$ of alkaline earth metal fluorides: Solubility increases down the group due to the hydration energy decreasing less rapidly than the lattice energy. Thus,$BeF_2 > CaF_2 > MgF_2$ is not the trend; rather,$MgF_2$ is the least soluble. The order $MgF_2 $3$. Therefore,option $A$ represents the correct trends.

Choose the correct order for the given property.
$M.P. \to$ Melting Point; $S \to$ Solubility

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Choose the correct order for the given property.$M.P. \to$ Melting Point; $S \to$ Solubility