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(D) The orbital period $T$ of a satellite is given by the formula: $T = 2\pi \sqrt{\frac{r^3}{GM}}$Squaring both sides,we get: $T^2 = 4\pi^2 \frac{r^3

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Mass of the earth,time period of the satellite and the gravitational constant

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(D) The orbital period $T$ of a satellite is given by the formula: $T = 2\pi \sqrt{\frac{r^3}{GM}}$Squaring both sides,we get: $T^2 = 4\pi^2 \frac{r^3}{GM}$Rearranging the equation to solve for the orbital radius $r$: $r^3 = \frac{GMT^2}{4\pi^2}$Therefore,$r = \left( \frac{GMT^2}{4\pi^2} \right)^{1/3}$From this expression,it is clear that the radius $r$ depends only on the mass of the Earth $(M)$,the gravitational constant $(G)$,and the time period of the satellite $(T)$. It is independent of the mass of the satellite $(m)$.

Choose the correct statement from the following: The radius of the orbit of a geostationary satellite depends upon

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