Choose the incorrect relation(s) from the fol | vedclass

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(D) To compare the values,we use the approximate values of the square roots:$\sqrt{2} \approx 1.414$$\sqrt{3} \approx 1.732$$\sqrt{5} \approx 2.236$$\

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$(i)$ and $(iii)$

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(D) To compare the values,we use the approximate values of the square roots:$\sqrt{2} \approx 1.414$$\sqrt{3} \approx 1.732$$\sqrt{5} \approx 2.236$$\sqrt{6} \approx 2.449$Now,calculate the sums:$\sqrt{6} + \sqrt{2} \approx 2.449 + 1.414 = 3.863$$\sqrt{5} + \sqrt{3} \approx 2.236 + 1.732 = 3.968$Comparing the two sums:$3.863 Therefore,$\sqrt{6} + \sqrt{2} This means statement $(ii)$ is correct,while statements $(i)$ and $(iii)$ are incorrect.

Choose the incorrect relation$(s)$ from the following:
$(i)$ $\sqrt{6}+\sqrt{2}=\sqrt{5}+\sqrt{3}$
$(ii)$ $\sqrt{6}+\sqrt{2}<\sqrt{5}+\sqrt{3}$
$(iii)$ $\sqrt{6}+\sqrt{2}>\sqrt{5}+\sqrt{3}$

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Choose the incorrect relation$(s)$ from the following:$(i)$ $\sqrt{6}+\sqrt{2}=\sqrt{5}+\sqrt{3}$$(ii)$ $\sqrt{6}+\sqrt{2}<\sqrt{5}+\sqrt{3}$$(iii)$ $\sqrt{6}+\sqrt{2}>\sqrt{5}+\sqrt{3}$